ElectrostaticsHard

Question

Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. Likely charged plates are then connected. Then, the decrease in energy of the combined system is

Options

A. C(V12 - V22)
B. C(V12 + V22)
C. C(V12 - V2)2
D. C(V12 + V2)2

Solution

ᐃ U = decrease in potential energy
= Ui - Uf
= C(V12 + V22) - (2C) = C(V1 - V2)2

Create a free account to view solution

View Solution Free
Topic: Electrostatics·Practice all Electrostatics questions

More Electrostatics Questions

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed ...A positively charged body ′A′ has been brought near a neutral brass sphere B mounted on a glass stand as sho...An electrical mass me, initially at rest, moves through a certain diatnce in a uniform electric field in time t1. A prot...Three concentric conducting spherical shells have radius r, 2r and 3r, and Q1, Q2 and Q3 are final charges respectively....If the electric flux entering and leaving an enclosed surface respectively is φ1 and φ2 the electric charge in...