Geometrical OpticsHard
Question
A concave lens of glass, refrective index 1.5 has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a
Options
A.convergent lens of focal length 3.5 R
B.convergent lens of focal length 3.0 R
C.divergent lens of focal length 3.5 R
D.divergent lens of focal length 3.0 R
Solution
R1 = - R, R2 = + R, μg = 1.5 and μm = 1.75
∴
Substituting the values, we get
=
∴ f = 03.5R
Therefore, in the medium it will behave like a convergent lens of focal length 3.5 R. It can be understood as μm > μg, the lens will change its behaviour.
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