Trigonometric EquationHard
Question
Distance between line L & plane P where L :
& P : 3x - 2z = 1 is equal to-
Options
A.
B.
C.
D.
Solution
D.r′s of line are (2,1,3)
⇒ || vector =
(say)
Normal to plane P is

L is || to P
Distance of L & P is distance of (1,0,2) on L from P
d =
⇒ || vector =
Normal to plane P is
L is || to P
Distance of L & P is distance of (1,0,2) on L from P
d =
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Area bounded by y = 2x2 & y = will be (in square unit)...The general solution of the trigonomrtirc equation sin x + cos x = 1 is diven by...Number of ordered pairs (a, x) satisfying the equation sec2 (a + 2) x + a2 − 1 = 0; − π < x < 	...If 0 ≤ x ≤ 3π, 0 ≤ y ≤ 3π and cos x . sin y =1 then the possible number of values of t...The normal to the curve x = a(cosθ + θ sinθ), y = a( sinθ - θ cosθ) at any point ′&#...