Trigonometric EquationHard
Question
The equation of the bisector of the acute angle between the lines 2x - y + 4 = 0 and x - 2y = 1 is :-
Options
A.x + y + 5 = 0
B.x - y + 1 = 0
C.x - y - 5 = 0
D.None of these
Solution
The equations of the lines are
2x - y + 4 = 0 and - x + 2y + 1 = 0
We have, 2 × - 1 + (-1) × 2 < 0 i.e. a1a2 + b1b2 < 0
Therefore, the equation of the bisector of acute angles is
⇒ 2x - y + 4 = - x + 2y + 1
⇒ 3x - 3y + 3 = 0
⇒ x - y + 1 = 0
2x - y + 4 = 0 and - x + 2y + 1 = 0
We have, 2 × - 1 + (-1) × 2 < 0 i.e. a1a2 + b1b2 < 0
Therefore, the equation of the bisector of acute angles is
⇒ 2x - y + 4 = - x + 2y + 1
⇒ 3x - 3y + 3 = 0
⇒ x - y + 1 = 0
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Let L be the line of intersection of the planes 2x + 3y + z = 1 and x + 3y + 2z = 2. If L makes an angles α with th...The general solution of the equation sin50x − cos50x = 1 is-...If 2 tan2θ = sec2θ, then the general value of θ is -...The number of solution of tan x + sec x = 2cos x in [0, 2π) is...(sin 3A + sinA) sin A + (cos3A - cosA) cos A = .......