Wave motionEasy

Question

A transverse sinusoidal wave of amplitude a, wavelength λ and frequency f is travelling on a stretched string. The maximum speed of any point on the string is v/10, where v is the speed of propagation of the wave. If a = 10-3 and v = 10 m/s, then λ and are given by

Options

A.λ = 2π × 10-2 m
B.λ = 10-3 m
C.f = Hz
D.f = 104

Solution

Maximum speed of any point on the string is = aω
      = a(2πf)
∴     = (Given : v = 10 m/s)
∴     a2πf = 1
∴     f =
    a = 10-3 m
∴     f =
      Hz
Speed of wave v = fλ
∴     (10m/s) = λ
∴     λ = 2π × 10-2 m

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