Sound WavesHard
Question
A transverse sinusoidal wave of amplitude a, wavelength λ and frequency f is travelling on a stretched string. The maximum speed of any point on the string is v/10, where v is the speed of propagation of the wave. If a = 10-3 and v = 10 m/s, then λ and are given by
Options
A.λ = 2π × 10-2 m
B.λ = 10-3 m
C.f = 
Hz
HzD.f = 104
Solution
Maximum speed of any point on the string is = aω
= a(2πf)
∴ =
(Given : v = 10 m/s)
∴ a2πf = 1
∴ f =
a = 10-3 m
∴ f =
Hz
Speed of wave v = fλ
∴ (10m/s) =
λ
∴ λ = 2π × 10-2 m
= a(2πf)
∴ =
(Given : v = 10 m/s)∴ a2πf = 1
∴ f =
a = 10-3 m
∴ f =
Hz Speed of wave v = fλ
∴ (10m/s) =
λ∴ λ = 2π × 10-2 m
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