Redox and Equivalent ConceptEasy
Question
The co-ordination number and oxidation state of Cr in K3[Cr(C2O4)3] are respectively :-
Options
A.3 and + 3
B.2 and 0
C.6 and + 3
D.4 and + 2
Solution
C.N. of Cr = 2 × 3 = 6
3 × 1 + x + 3(- 2) = 0
x - 3 = 0
[x = + 3]
3 × 1 + x + 3(- 2) = 0
x - 3 = 0
[x = + 3]
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