Momentum and CollisionHard

Question

A metal ball immersed in alcohal weigh W1 at 0o and W2 at 50o. The coefficient of cubical expension of the metal is less than the alcohol. Asssuming that the density of the metal is large compared to that of alcohol, it can be shown that

Options

A.W1 > W2
B.W1 = W2
C.W1 < W2
D.All of these

Solution

Wapp = Wactual - Upthrust
Upthrust F = V′sρ′Lg
Here, Vs = volume of solid, ρL = density of liquid
At higher temperature F′ = V′sρ′Lg
∴    
Since,       γs > L       (given)
∴ F′ > F       or       W′app > Wapp

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