CapacitanceEasy
Question
For the circuit shown in fig. Calculate the charge on 8μF capacitor
Options
A.20 μm
B.10 μm
C.4 μm
D.2 μm
Solution
When capacitor is fully charged there will be no flow of current through capacitor.
so current in circuit
I =
A
voltage across 8μF capacitor = 10
- 1
=
volt
so charge Q = CV = (8 × 10-6)
= 2μC
so current in circuit
I =
Avoltage across 8μF capacitor = 10
- 1 =
voltso charge Q = CV = (8 × 10-6)
= 2μCCreate a free account to view solution
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