CapacitanceHard
Question
For the circuit shown in fig. Calculate the charge on 8μF capacitor


Options
A.20 μm
B.10 μm
C.4 μm
D.2 μm
Solution
When capacitor is fully charged there will be no flow of current through capacitor.
so current in circuit
I =
A
voltage across 8μF capacitor = 10
- 1
=
volt
so charge Q = CV = (8 × 10-6)
= 2μC
so current in circuit
I =
voltage across 8μF capacitor = 10
=
so charge Q = CV = (8 × 10-6)
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