Rotational MotionHard
Question
One quarter section is cut from a uniform circular disc of radius R. This section has a mass M. It is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. Its moment of inertial about the axis of rotation is
Options
A.
MR2
MR2B.
MR2
MR2C.
MR2
MR2D.√2MR2
Solution
Mass of the whole disc = 4M
Moment of inertia of the disc about the given axis
(4M R2) = 2MR2
∴ Moment of inertia of quarter section of the disc
=
(2MR2) = MR2
Moment of inertia of the disc about the given axis
(4M R2) = 2MR2∴ Moment of inertia of quarter section of the disc
=
(2MR2) = MR2Create a free account to view solution
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