Rotational MotionHard
Question
A mass m is moving with a constant velocity along a line parallel to the x-axis, away from the origin. Its angular momentum with respect to the origin
Options
A.zero
B.remains constant
C.goes on increasing
D.goes on decreasing
Solution
= v = constant and 
= r (say)Angular momentum of the particle about origing O will be given by
or,
= L = mrv sin θ = mv(r sinθ) = mvh Now, m, v and h all are constants.
Therefore, angular momentum of particle about origing will remain constant. The direction of
also remains the same (negative z).Create a free account to view solution
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