p-Block elementsHard

Question

If LPG cylinder contains mixture of butane and isobutane, then the amount of oxygen that would be required for combustion of 1 kg of it will be:-

Options

A.1.8 kg
B.2.7 kg
C.4.5 kg
D.3.58 kg

Solution

C4H10 + O2 → 4CO2 + 5H2O
58 g   13 × 16g
∵  Oxygen required for combustion of 58 g butane = 13 × 16 g
∴  Oxygen required for combustion of 1 kg butane = kg = 3.586 kg

Create a free account to view solution

View Solution Free
Topic: p-Block elements·Practice all p-Block elements questions

More p-Block elements Questions