p-Block elementsEasy
Question
If LPG cylinder contains mixture of butane and isobutane, then the amount of oxygen that would be required for combustion of 1 kg of it will be:-
Options
A.1.8 kg
B.2.7 kg
C.4.5 kg
D.3.58 kg
Solution
C4H10 + 
O2 → 4CO2 + 5H2O
58 g 13 × 16g
∵ Oxygen required for combustion of 58 g butane = 13 × 16 g
∴ Oxygen required for combustion of 1 kg butane =
kg = 3.586 kg
O2 → 4CO2 + 5H2O58 g 13 × 16g
∵ Oxygen required for combustion of 58 g butane = 13 × 16 g
∴ Oxygen required for combustion of 1 kg butane =
kg = 3.586 kgCreate a free account to view solution
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