Atomic StructureHard
Question
Beryllium fourth electron will have the four quantum numbers :-
Options
A.n → 1
l → O
m → O
s → 1/2
l → O
m → O
s → 1/2
B.n → 1
l → 1
m → 1
s → 1/2
l → 1
m → 1
s → 1/2
C.n → 2
l → O
m → O
s → -1/2
l → O
m → O
s → -1/2
D.n → 2
l → 1
m → O
s → +1/2
l → 1
m → O
s → +1/2
Solution
4Be → 1s22s2
Fourth electron present in 2s subshell
for 2s subshell, n = 2, l = 0, m = 0 s = - 1/2 or + 1/2
Fourth electron present in 2s subshell
for 2s subshell, n = 2, l = 0, m = 0 s = - 1/2 or + 1/2
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