JEE AdvancedWork, Power and EnergyEasy
Question
A force 
, (where k is a positve constant) acts on a particle moving in the x-y plane. String from the origin, the particle is taking along the positve x-axis to the point (a, o) and parallel to the y-axis to the point (a, a). The total work done by the force F on the particle is
, (where k is a positve constant) acts on a particle moving in the x-y plane. String from the origin, the particle is taking along the positve x-axis to the point (a, o) and parallel to the y-axis to the point (a, a). The total work done by the force F on the particle isOptions
A.- 2ka2
B.2ka2
C.- ka2
D.ka2
Solution
d W = 
where
and
∴ dW = - k(ydx + xdy) = - kd(xy)
∴ W =
d(xy) = - k[xy]
W = - ka2
whereand
∴ dW = - k(ydx + xdy) = - kd(xy)
∴ W =
d(xy) = - k[xy]W = - ka2
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