Work, Power and EnergyHard
Question
A particle of mass m is moving in a circular path of constant radius r such that its centrip-etal acceleration ac is varying with time t as ac = k2 r t2, where k is a constant. The power delivered to the particle by the force acting on it is
Options
A.2πmk2r2
B.mk2r2t
C.
D.zero
Solution
ac = k2r2
or
= k2rt2 or v = krt
Therefore, tangential acceleration, at =
= kr
or Tangential force, Ft = ma = mkr
Only tangential force does work
Power = Ftv = (mkr) = (krt)
or Power = mk2r2t
or
= k2rt2 or v = krtTherefore, tangential acceleration, at =
= kror Tangential force, Ft = ma = mkr
Only tangential force does work
Power = Ftv = (mkr) = (krt)
or Power = mk2r2t
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