Errors in measurementHard
Question
If the percentage error in the measurement of radius of a sphere is 2%, then the maximum percentage errors in the measurements of its diameter, surface area and volume are respectively
Options
A.2%, 4% and 4%
B.6%, 4% and 2%
C.6%, 6% and 6%
D.2%, 4% and 6%
Solution
∵ D = 2R ∴ 
× 100 = 
× 100 = 2%
∵ A = 4πR2 ∴
× 100 = 2 
× 100 = 4%
∵ V = 4/3 πR3 ∴
× 100 = 3 
× 100 = 6%
× 100 = × 100 = 2%∵ A = 4πR2 ∴
× 100 = 2 × 100 = 4%∵ V = 4/3 πR3 ∴
× 100 = 3 × 100 = 6%Create a free account to view solution
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