Work, Power and EnergyHard
Question
If the length of a heater wire of 1000W, 220V is reduced by 20% then the power consumption will be
Options
A.1250 W
B.1200 W
C.1000 W
D.800 W
Solution
L′ = 
L
so R′ =
R
and P′ =
(1000)
= 1250W
Lso R′ =
Rand P′ =
(1000)= 1250W
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