Circular MotionHard

Question

A long horizontal rod has a bead which can slide along its length and is initially placed at a distance L from one end A of the rod. The rod is set in angular motion about A with a constant angular acceleration α. If the coefficient of friction between the rod and bead is μ, and gravity is negligible, then the time after which the bead starts slipping is

Options

A.
B.
C.
D.infinitesimal

Solution

       
Tangential force (Ft) of the bead will be given by the normal reaction (N), while centripetal force (Fc) is provided by friction (fr). The bead starting sliding when the centripetal force is just equal to the limiting friction.
Therefore, Ft = ma = mαL = N
∴ Limiting value of friction
(fr)max = μ N = μmαL     ....(i)
Angular velocity at time t is ω = αt
∴ Centripetal force at time t will be
Fc = mLωt2 = mLα2t2     ....(ii)
Equating eqs (i) and (ii), we get
t =
For t > , Fc > (fr)max i.e., the bead stats sliding.
In the figure Fc is perpendicular to the paper inwards.

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