Circular MotionHard
Question
A block of mass 2 kg on a rough inclined plane making an angle of 30o with horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is
Options
A.9.8 N
B.0.7 × 9.8 × √3 N
C.9.8 × √3 N
D.0.7 × 9.8 N
Solution
Since, μ mg cos θ > mg sin θ
∴ Force of friction is f = mg sin θ
∴ Force of friction is f = mg sin θ
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