Analytical ChemistryHard
Question
Which onr amongst the following pairs of ions cannot be separated by H2S in dilute HCL ?
Options
A.Bi3+, Sn4+
B.Al3+, Hg2+
C.Zn2+, Cu2+
D.Ni2+, Cu2+
Solution
Which H2S is passed in presence of dil. HCl
(a) Sulphides of both Bi3+ and Sn4+ get precipitated and hence they can,t be separated.
(b) Sulphides of only Hg2+ is precipitated, hence they can be separated.
(c) Sulphides of only Cu2+ is precipitated, hence they can be separated .
(d) Sulphides of only Cu2+ is precipitated, hence they can be separated.
(a) Here NO shwo 1 + oxidation state thus
x + 5 × (0) + (1+) + 1 × (2-) = 0 ⇒ x = 1 + (O. No. of Fe )
(a) Sulphides of both Bi3+ and Sn4+ get precipitated and hence they can,t be separated.
(b) Sulphides of only Hg2+ is precipitated, hence they can be separated.
(c) Sulphides of only Cu2+ is precipitated, hence they can be separated .
(d) Sulphides of only Cu2+ is precipitated, hence they can be separated.
(a) Here NO shwo 1 + oxidation state thus
x + 5 × (0) + (1+) + 1 × (2-) = 0 ⇒ x = 1 + (O. No. of Fe )
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