Hydrogen and its compoundHard

Question

In nitroprusside ion and NO exist as FeII and NO+ rather than FeIII and NO. These forms can be differentiated by :

Options

A.estimating the concentration of iron
B.measuring the concentration of CN
C.measuring the solid state magnetic moment
D.thermally decomposing the complound

Solution

Presence of Fe as Fe (II) not as Fe (III) and NO as NO+ not as NO, can be confirmed by determining the number of unpaired electrons. If Fe and NO exist as (II) and NO+ then total number of unpaired electrons in the molecule will be 4 (Fe (II) = 4, NO+ = 0). If Fe (III) and NO are present, total number of unpaired electrons will be 6 (Fe (III) = 5, NO = 1). Magnetic moment of a molecule is directly related to the number of unpired electrons and is given by
       μ = Bohr Magneton
        n = No. of unpaired electron
Hwnce, the two cases may be differentiated by measuring magnetic moments.

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