p-Block elementsHard
Question
In compounds of type ECl3, where E = B, P As or Bi, the Cl - E - Cl bond angle for different E are in the order :
Options
A.B > P = As = Bi
B.B > P > As > Bi
C.B < P = As = Bi
D.B < P < As < Bi
Solution
Using different atoms assingned for E, the examples of halides are BCl3, PCl3, AsCl3 and BiCl3. In BCl3 the central B atom is sp2 hybridised and due to planar triangular geometry Cl - B - Cl angle is 120o (maximum).
In PCl3, AsCl3 and BiCl3, the central atpm is sp3 hybridised but the slight difference in angles (with slight deviation from normal tetrmal tetrahedral angle 109o28′) is due to difference in electronegativites of central atoms.
When electronegativity of central atom will be maximum, the bond pairs of E - Cl bonds will be shifted torward central atom and they will be situated closer to each other. It will lead to more bond pair-bond pair repulsion resulting in larger bond angle and vice versa.
Electromegativity of P, As and Bi follow the order :
P > As > Bi
thus correct order is BCl3 > PCl3 > AsCl3 > Bi
Here it is important to note that all the three halides of P, As and Bi, the bond angle is less than 109o28′ (normal terahedral angle). It is due to lp - bp repulsion. bp-bp repulsions are not so string to exceed the Cl - E - Cl bond angle larger than 109o28′
In PCl3, AsCl3 and BiCl3, the central atpm is sp3 hybridised but the slight difference in angles (with slight deviation from normal tetrmal tetrahedral angle 109o28′) is due to difference in electronegativites of central atoms.
When electronegativity of central atom will be maximum, the bond pairs of E - Cl bonds will be shifted torward central atom and they will be situated closer to each other. It will lead to more bond pair-bond pair repulsion resulting in larger bond angle and vice versa.
Electromegativity of P, As and Bi follow the order :
P > As > Bi
thus correct order is BCl3 > PCl3 > AsCl3 > Bi
Here it is important to note that all the three halides of P, As and Bi, the bond angle is less than 109o28′ (normal terahedral angle). It is due to lp - bp repulsion. bp-bp repulsions are not so string to exceed the Cl - E - Cl bond angle larger than 109o28′
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