SolutionHard
Question
1.8 gm of fructose is added to 2kg of water. The freezing point of the solution is :-
(Kf = 1.86 K molality-1)
(Kf = 1.86 K molality-1)
Options
A.-1.86oC
B.0.0093oC
C.-0.0186oC
D.-0.0093oC
Solution
ᐃTf = Kf m
= 1.86 ×
= 0.0093
F.P. = 0 - 0.0093 = - 0.0093oC
= 1.86 ×
= 0.0093F.P. = 0 - 0.0093 = - 0.0093oC
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