Hydrogen and its compoundHard
Question
Calculate the amount of ammonium chloride required to dissolve in 500 ml water to have pH = 4.5 (Kb for NH4OH is 1.8 × 10-5) :-
Options
A.1.8 g
B.0.9 g
C.48.15 g
D.45.15 g
Solution
pH = 7 - 
pKb - 
log C
4.5 = 7 -
log C
- 0.13 = -
logC
C = 1.80 mol/litre
Amount in 500 mL = 1.80 × 0.5 × 53.5 = 48.15g
pKb - log C4.5 = 7 -
log C- 0.13 = -
logCC = 1.80 mol/litre
Amount in 500 mL = 1.80 × 0.5 × 53.5 = 48.15g
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