Current Electricity and Electrical InstrumentHard
Question
In an LCR circuit as shown below both switches are open initially. Now switch S1 is closed, S2 kept open, (q is charge on the capacitor and 
is Capacitive time constant). Which of the following statement is correct ?
is Capacitive time constant). Which of the following statement is correct ?Options
A.Work done by the battery is half of the energy dissipated in the resistor
B.At t= 
, q = CV/2
, q = CV/2C.At t = 
,q = CV(1-e-2)
,q = CV(1-e-2) D.At 
, q = CV(1-e-1)
, q = CV(1-e-1)Solution
For charging of capacitor
q = q0 (1 - e- t/
) = CV (1 - e- t/)
at t =, q = CV(1 - e-2)
q = q0 (1 - e- t/
) = CV (1 - e- t/)at t =
, q = CV(1 - e-2)Create a free account to view solution
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