SolutionHard
Question
x mole of KCI and y mole of BaCl2 are both dissolved in 1 kg of water. Given that x + y = 0.1 and Kf for water is 1.85 K/molal, what is the observed range of ᐃTf, if the ratio of x to y is varied ?
Options
A.0.37o to 0.505o
B.0.185o to 0.93o
C.0.56o to 0.93o
D.0.37o to 0.93o
Solution
x + y = 0.1
x / y = 0.37
ᐃTf =
× 1000 × 1.85
ᐃTf =
× 1000 × 1.85
ᐃTf = (0.2 + 0.0729927) × 1.85 = 0.505
x / y = 0.37
ᐃTf =
× 1000 × 1.85ᐃTf =
× 1000 × 1.85ᐃTf = (0.2 + 0.0729927) × 1.85 = 0.505
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