SolutionHard
Question
A 0.2 molal aqueous solution of a weak acid (HX) is 20 per cent ionised. The freezing point of this solution is (Given kf = 1.86oC kg mol-1 for water) :
Options
A.-0.45oC
B.- 0.90oC
C.- 0.31oC
D.- 0.53oC.
Solution
ᐃTf = 0.2 × 1.2 × 1.86 = 0.45
therefore freezing point = - 0.45oC.
therefore freezing point = - 0.45oC.
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