HydrocarbonsHard

Question

A hydrocarbon, ′X′(C3H4) decolourise bromine in carbon tetrachloride forming ′Y′ . ′X′  gave a red precipitate of a compound ′Z′ with ammonical cuprous chloride and formed a carbonyl compound with dilute sulphuric acid in the presence of Hg+2 ions. X, Y, and Z are given by the set −

Options

A.CH2 = C = CH2,  CH2Br - CBr2 - CH2Br, CH3 - C ≡ C - Cu
B.CH3 − C ≡ CH, CH3 − CBr2 − CHBr2, CH3 − C ≡ C − Cu
C.CH3 − C ≡ CH, CH3 − CBr = CHBr, CH2Cu − C ≡ CH
D.CH2 = C = CH2, CH2Br − CH = CHBr, CH3 − C ≡ C − Cu

Solution

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