MetallurgyHard
Question
In Van Arkel method, if I2 is introduced at 1800 K over impure zirconium metal, the product will be :
Options
A.iodide of the metal
B.pure metal
C.impurities react with iodine
D.none of these
Solution
Zr (impure) + 2I2 
ZrI4 ; ZrI4 
Zr (pure) + 2I2 and hence over 1800oC practically no reaction can take place between Zr and I2.
Therefore, (D) option is correct.
ZrI4 ; ZrI4 Zr (pure) + 2I2 and hence over 1800oC practically no reaction can take place between Zr and I2.Therefore, (D) option is correct.
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