MetallurgyHard
Question
On the basis of ellingham diagram which of the following is/are correct.
Options
A.Entropy change for all metal oxides is roughly same.
B.Below the boiling point, ′TᐃS′ factor is same irrespective of metal.
C.Above ᐃG = 0 line, oxide decomposes into metal & oxygen.
D.If randomness increases the slope increases
Solution
(A) 
= - ᐃS, 
is slope in Ellingham diagram. Which is same below the boiling point.
(B) Below the boiling point slope is same as factor TᐃS is same.
(C) Above ᐃG = 0 line free energy becomes positive so oxide decomposes.
(D) Random increases i.e. ᐃS increases, so slope also increases.
= - ᐃS, is slope in Ellingham diagram. Which is same below the boiling point.(B) Below the boiling point slope is same as factor TᐃS is same.
(C) Above ᐃG = 0 line free energy becomes positive so oxide decomposes.
(D) Random increases i.e. ᐃS increases, so slope also increases.
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