Photoelectric EffectHard
Question
A source S1 is producing, 1015 photons per second of wavelength 5000 
. Another source S2 is producing 1.2 × 1015 photons per second of wavelength 5100 . Then,(power of S2)/(power of S1) is equal to
. Another source S2 is producing 1.2 × 1015 photons per second of wavelength 5100 . Then,(power of S2)/(power of S1) is equal toOptions
A.1.00
B.1.02
C.1.04
D.0.98
Solution
For a source S1
Wavelength, λ1 = 5000
Number of photons emitted per second, N1 = 1015
Energy of each photon, E1 =
Power of source S1, P1 = E1N1
For a source S2
Wavelength, λ2 = 5100
Number of photons emitted per second, N2 = 1.02 × 1015
Energy of each photon, E2 =
Power of source S2, P2 = E2N2
∴
Wavelength, λ1 = 5000
Number of photons emitted per second, N1 = 1015
Energy of each photon, E1 =
Power of source S1, P1 = E1N1
For a source S2
Wavelength, λ2 = 5100
Number of photons emitted per second, N2 = 1.02 × 1015
Energy of each photon, E2 =
Power of source S2, P2 = E2N2
∴
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