JEE AdvancedAlternating CurrentMedium
Question
In the given circuit the reading of voltmeter V1 and V2 are 300 volts each. The reading of the voltmeter V3 and ammeter A are respectively
Options
A.150 V, 2.2 A
B.220 V, 2.2 A
C.220 V, 2.0 A
D.100 V, 2.0 A
Solution

As 300 VL = VC = 300V, therefore the given series LCR circuit is in resonance.
∴ VR = Vc = 220 V
Z = R = 100Ω
Current, I =
= 2.2 AHence, the reading of voltmeter V3 is 220 V and the reading of ammeter A is 2.2 A.
Create a free account to view solution
View Solution FreeMore Alternating Current Questions
The power factor of an AC circuit having resistance (R) and inductance (L) connected in series and an angular velocity &...An inductance L having a resistance R is connected to an alternating source of angular frequency ω . The Qulity factor...A coil has resistance 30Ω and inductive resistance 20Ω at 50 Hz frequency. If an ac source, of 200 volt, 100 H...Number of turns in primary coil of a transformer is 240. When input voltage is 20 volt, then output voltage is 2.5 volt....An a.c. source of angular frequency $\omega$ is connected across a resistor R and a capacitor C in series. The current i...