Analytical ChemistryHard
Question
Cu2+ ions will be reduced to Cu+ ions by the addition of an aqueous solution of :
Options
A.KI
B.KCl
C.KSCN
D.KCN
Solution
2CuSO4 + 4KI → 2CuI ↓ (white) + 2K2SO4 + I2
3SCN- + Cu2+ → CuSCN ↓ (white) + (SCN)2
6CN- + Cu2+ → [Cu(CN)4]3- + (CN)2
3SCN- + Cu2+ → CuSCN ↓ (white) + (SCN)2
6CN- + Cu2+ → [Cu(CN)4]3- + (CN)2
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