Analytical ChemistryHard
Question
Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dilute NaCl solution and one formed a black precipitate with H2S. The salt could be :
Options
A.AgNO3
B.Pb(NO3)2
C.Hg(NO3)2
D.Mn(NO3)2
Solution
Pb(NO3)2 + 2NH4OH → Pb(OH)2 ↓ (white) + 2NH4NO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
Create a free account to view solution
View Solution FreeMore Analytical Chemistry Questions
When H2S is passed through Hg2S we get...Identify the compound which turns black with ammonia solution....Which of the following solutions give white precipitate with Pb(NO3)2 as well as with Ba(NO3)2 ?...Which of the following sulphides do not dissolve in 50% HNO3 but dissolve in aquaregia ?...Which of the following reagents gives white precipitate with Hg(NO3)2 solution ?...