Analytical ChemistryHard
Question
Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dilute NaCl solution and one formed a black precipitate with H2S. The salt could be :
Options
A.AgNO3
B.Pb(NO3)2
C.Hg(NO3)2
D.Mn(NO3)2
Solution
Pb(NO3)2 + 2NH4OH → Pb(OH)2 ↓ (white) + 2NH4NO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
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