Analytical ChemistryHard
Question
Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dilute NaCl solution and one formed a black precipitate with H2S. The salt could be :
Options
A.AgNO3
B.Pb(NO3)2
C.Hg(NO3)2
D.Mn(NO3)2
Solution
Pb(NO3)2 + 2NH4OH → Pb(OH)2 ↓ (white) + 2NH4NO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + 2NaCl → PbCl2↓ (white) + 2NaNO3
Pb(NO3)2 + H2S → PbCl2↓ (white) + 2NaNO3
Create a free account to view solution
View Solution FreeMore Analytical Chemistry Questions
When chlorine (Cl2) water in excess is added to a salt solution containing chloroform, chloroform layer turns pale yello...In the Group analysis of cations, ${Ba}^{2 +}\&{Ca}^{2 +}$ are precipitated respectively as...AgCl dissolves in ammonia solution giving :...Fe(OH)3 and Cr(OH)3 precipitates can be completely separated by :...Which one among the following pairs of ions can not be separated by H2S in presence of dilute hydrochloric acid ?...