Analytical ChemistryHard
Question
An inorganic compound ′A′ is dissolved in dilute hydrochloric acid and is then warmed. A colourless gas ′B′ is produced. When a filter paper moistened with potassium iodate and the starch solution is exposed to the gas it turns blue. The gas B and the compound A are :
Options
A.SO2 and Na2SO3
B.SO3 and Na2SO4
C.H2S and Na2S
D.H2S and Na2SO3
Solution
SO32- + 2H+ → SO2 ↑ + H2O
SO2 + 2IO3- + 4H2O → I2 + 5SO4-2 + 8H+
Thus the gas B and compound A are SO2 and Na2SO3 respectively.
SO2 + 2IO3- + 4H2O → I2 + 5SO4-2 + 8H+
Thus the gas B and compound A are SO2 and Na2SO3 respectively.
Create a free account to view solution
View Solution FreeMore Analytical Chemistry Questions
Nitrite (NO2-) interferes in the ′ring-test′ of nitrate (NO3-). Some of the following reagents can be used f...An aqueous solution of salt containing an acidic radical X- reacts with sodium hypochlorite in neutral medium. The gas e...Which one of the following salts will produce clear and transparent original solution in 2M HCl ?...When HNO3 is added to sodium ferrocyanide, which of the following observation is observed ?...A mixture of two salts is not water soluble but dissolves completely in dilute HCl to form a colourless solution. The mi...