SHMHard
Question
The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
A.T
B.

C.2T
D.√2T
Solution
A mass M is suspended from a massless spring of constant k as shown figure (a). Then
Time period of oscillation is T = 2π
.......(i)
When a another mass M is also suspended with it as shown in figure (b).
Then Time period of oscillation is
T′ = 2π

√2T [using (i)]

Time period of oscillation is T = 2π
.......(i)When a another mass M is also suspended with it as shown in figure (b).
Then Time period of oscillation is
T′ = 2π


√2T [using (i)]

Create a free account to view solution
View Solution FreeMore SHM Questions
A body executing SHM passes through its equilibrium. At this instant, it has...The function sin2(ωt) represents...A mass of 4.0 kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in figure. The mass of ...Some springs are combined in series and parallel arrangement as shown in the figure and a mass m is suspended from them....Two particles execute S.H.M. of same amplitude and frequency along the same straight line from same mean position. They ...