ElectroMagnetic InductionHard
Question
Initially key was placed on (1) till the capacitor got fully charged. Key is placed on (2) at t = 0. The time when the energy in both capacitor and inductor will be same-
Options
A.
B.
C.
D.
Solution
For given situation 
+ ω2q = 0 ⇒ q = q0 cos ωt & i = - q0ωsinωt
According to given conditions
Lq02ω2 sin2 ωt
⇒ cot2ωt = 1 ⇒ ωt =
......... ⇒ t = 
...
+ ω2q = 0 ⇒ q = q0 cos ωt & i = - q0ωsinωtAccording to given conditions
Lq02ω2 sin2 ωt⇒ cot2ωt = 1 ⇒ ωt =
......... ⇒ t = ...Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A circular loop of radius r is moved with a velocity v as shown in the diagram. The work needed to maintain its velocity...The current in a coil of 0.4 mH coil increases by 250 mA in 0.1 second. The induced emf will be :-...A long conductor AB lies along the axis of a circular loop of radius R. If the current in the conductor AB varies at the...A coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ. This combination i...Dimension of a ractangular coil is 20 cm × 10 cm. Number of turns in coil is 60. It is rotating about its one of th...