ElectroMagnetic InductionHard
Question
Initially key was placed on (1) till the capacitor got fully charged. Key is placed on (2) at t = 0. The time when the energy in both capacitor and inductor will be same-
Options
A.
B.
C.
D.
Solution
For given situation 
+ ω2q = 0 ⇒ q = q0 cos ωt & i = - q0ωsinωt
According to given conditions
Lq02ω2 sin2 ωt
⇒ cot2ωt = 1 ⇒ ωt =
......... ⇒ t = 
...
+ ω2q = 0 ⇒ q = q0 cos ωt & i = - q0ωsinωtAccording to given conditions
Lq02ω2 sin2 ωt⇒ cot2ωt = 1 ⇒ ωt =
......... ⇒ t = ...Create a free account to view solution
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