ElectroMagnetic InductionHard
Question
The potential difference V and current I flowing through the AC circuit is given by V = 5 cos(ωt - π/6) volt and I = 10sinωt ampere. The average power dissipated in the circuit is
Options
A.
B.12.5 W
C.25 W
D.50 W
Solution
V = 5 cos (ωt - π/6); i = 10 sin ωt = 10 cos (ωt - π/2)
; P =
= 12.5 W
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