ElectroMagnetic InductionHard

Question

The potential difference V and current I flowing through the AC circuit is given by V = 5 cos(ωt - π/6) volt and I = 10sinωt ampere. The average power dissipated in the circuit is

Options

A.
B.12.5 W
C.25 W
D.50 W

Solution

V = 5 cos (ωt - π/6); i = 10 sin ωt = 10 cos (ωt - π/2)
; P = = 12.5 W

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