Rotational MotionHard
Question
Two spheres each of mass M and radius R/2 are connected with a mass less rod of length 2R as shown in the-figure. What will be the moment of inertia of the system about an axis passing through the centre of one of the spheres and perpendicular to the rod
Options
A.
B.
C.
D.
Solution
MI of system :
I = Isphere + Isphere + M × (2R)2
=
I = Isphere + Isphere + M × (2R)2
=
Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
A ring and a solid sphere of same mass and radius are rotating with the same angular velocity about their diameteric axe...A particle of mass m moves with a constant velocity. Which of the following statements is not correct about its angular ...A stone attached to one end of string is revolved around a stick so that the string winds upon the stick and gets shorte...Figure shows a uniform disk, with mass M = 2.4 kg and radius R = 20 cm, mounted on a fixed horizontal axle. A block of m...The moment of inertia of a ring about an axis passing through is centre and normal to its face is 200 g-cm2. Then its mo...