Rotational MotionHard
Question
Two spheres each of mass M and radius R/2 are connected with a mass less rod of length 2R as shown in the-figure. What will be the moment of inertia of the system about an axis passing through the centre of one of the spheres and perpendicular to the rod
Options
A.
B.
C.
D.
Solution
MI of system :
I = Isphere + Isphere + M × (2R)2
=
I = Isphere + Isphere + M × (2R)2
=
Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
On meltng of ice on the pole of the earth, its moment of inertia will :-...In the above question, the change in angular momentum of disc in first 2 seconds in Nm second will be -...Moment of inertia of a circular wire of mass M and radius R about its diameter is...The moment of inertia of a thin uniform rod of mass M and length L about an axis passingthrough its midpoint and perpend...Calculate the ratio of the times taken by a uniform solid sphere and a disc of the same mass and the same diameter to ro...