Rotational MotionHard
Question
A particle of mass m is projected with a velocity v making an angle of 45o with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height is : -
Options
A.zero
B.
C.
D.m 
Solution
Max height 
Angular momentum
= mv cos45o ×
Angular momentum
= mv cos45o ×
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