Rotational MotionHard
Question
A uniform rod of mass M and length L lies radially on a disc rotating with angular speed ω in a horizontal plane about its axis. The rod does not slip on the disc and the centre of the rod is at a distance R from the centre of the disc. Then the kinetic energy of the rod is -
Options
A.
B.
mω2R2
mω2R2C.
mω2L2
mω2L2D.None of these
Solution
As rod does not slip on the disc, so the kinetic energy of the rod is
=
I - MI of rod about axis passing through centre of disc & perpendicular to the plane.
=
I - MI of rod about axis passing through centre of disc & perpendicular to the plane.
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