VectorMedium
Question
The dimensions of 
ε0E2, where ε0 is permitivity of free space and E is electric field, is
ε0E2, where ε0 is permitivity of free space and E is electric field, is Options
A.ML2T-2
B.ML-1T-2
C.ML2T-1
D.MLT-1
Solution
Energy density of an electric field E is uE = ε0E2
where ε0 is permittivity of free space uE = ML-1T-2
Hence, the dimension ofε0E2 is ML-1T-2
ε0E2where ε0 is permittivity of free space uE = ML-1T-2
Hence, the dimension of
ε0E2 is ML-1T-2Create a free account to view solution
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