Rotational MotionHard

Question

A weightless rod is acted on by upward parallel forces of 2N and 4N at ends A and B respectively. The total length of the rod is AB = 3 m. To keep the rod in equilibrium a force of 6N should act in the following manner : -

Options

A.Downwards at any point between A and B
B.Downwards at mid point of AB
C.Downwards at a point C such that AC = 1m
D.Downwards at a point D such that BD = 1m

Solution


or equilibrium the
∴ (4 - 2) × 1.5) ⇒ x = m

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