Rotational MotionHard

Question

If the earth is a point mass of 6 × 1024 kg revolving around the sun at a distance of 1.5 × 108 km and in time T = 3.14 × 107 second, then the angular momentum of the earth around the sun is : -

Options

A.1.2 × 1018 kg m2/s
B.1.8 × 1020 kg m2/s
C.1.5 × 1037 kg m2/s
D.2.7 × 1040 kg m2/s

Solution

⇒ I = mearth r2 = 6 × 1024  (1.5 × 108)2

∴ 2.7 × 1040 kg m2/s

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