Rotational MotionHard
Question
Four similar point masses (each of mass m) are placed on the circumference of a disc of mass M and radius R. The M.I. of the system about the normal axis through the centre O will be : -
Options
A.MR2 + 4mR2
B.
MR2 + 4mR2
MR2 + 4mR2C.MR2 + 
mR2
mR2D.None of these
Solution
MI of disc about the axis at O & Perpendicular to
plane is =
MI of four particle is = mR2 × 4
∴ Total MI =
+ 4mR2
plane is =
MI of four particle is = mR2 × 4∴ Total MI =
+ 4mR2Create a free account to view solution
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