JEE AdvancedElectroMagnetic InductionHard
Question
A condenser of capacity C is charged to a potential difference of V1 The plates of the condenser are connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V2 is
Options
A.
B.
C.
D.
Solution
In case of oscillatory discharge of a capacitor through an inductor, charge at instant t is given by
q = q0 cos ωt
Where, ω =
∴ cosωt =
(∵ q = CV) ........(i)
Current through the inductor
I =
(q0 cos ωt) = - q0ωsin ωt
|I| = CVI l
[1 - cos2 ωt]1/2
= V1
(using (i))
q = q0 cos ωt
Where, ω =
∴ cosωt =
(∵ q = CV) ........(i)Current through the inductor
I =
(q0 cos ωt) = - q0ωsin ωt |I| = CVI l
[1 - cos2 ωt]1/2 = V1
(using (i))Create a free account to view solution
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