Magnetic field due to currentHard
Question
A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width d = 
at angle 53o to the boundary of magnetic field. Find the angle θ in the diagram.
at angle 53o to the boundary of magnetic field. Find the angle θ in the diagram. Options
A.37o
B.60o
C.90o
D.None
Solution
Rsinδ = d
sin δ = 
δ = 37o
∴ θ = 53o + δ = 90o
sin δ = δ = 37o
∴ θ = 53o + δ = 90o
Alternative method:
R cosθ − R cos φ = d ( θ = angle of incidence ,φ = Angle of emergence)
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