Magnetic field due to currentMedium
Question
A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width d = 
at angle 53o to the boundary of magnetic field. Find the angle θ in the diagram.
at angle 53o to the boundary of magnetic field. Find the angle θ in the diagram. Options
A.37o
B.60o
C.90o
D.None
Solution
Rsinδ = d
sin δ = 
δ = 37o
∴ θ = 53o + δ = 90o
sin δ = δ = 37o
∴ θ = 53o + δ = 90o
Alternative method:
R cosθ − R cos φ = d ( θ = angle of incidence ,φ = Angle of emergence)
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
A battery is connected between two points A and B on the circuimference of a uniform conducting ring of radius r and res...A square of side L meters lies in the x-y plane in a region, where the magnetic field is given by where B0 is constant. ...An electron is moving around a proton in an orbit of radius 1 and produces 16 Wb/m2 of magnetic field at the centre, the...Two concentric coils of 10 turns each are situated in the same plane. The radii are 20 cm and 40 cm and they carry respe...A long solenoid has 200 turns per cm and carries a current i. The magnetic field at its centre is 6.28 × 10-2 Weber...