Magnetic field due to currentHard
Question
In a region of space, a uniform magnetic field B exists in the y-direction. A proton is fired from the origin, with its initial velocity v making a small angle αwith the y-direction in the yz plane. In the subsequent motion of the proton
Options
A.its x-coordinate can never be positive
B.its x- and z-coordinates cannot both be zero at the same time
C.its z- coordinate can never be negative
D.its y-coordinate will be proportional to the square of its time of flight
Solution
= q(v cos αĵ + v sin α
) × Bĵ = qvB sin α (- î)Hence the x coordinate of proton can never be + ve.
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