Magnetic field due to currentHard
Question
A particle of specific charge (charge/mass) α starts moving from the origin under the action of an electric field 
= E0ĵ and magnetic field 
= B0 
. Its velocity at (x0, y0, 0 ) is (4î - 3ĵ). The value of x0 is
= E0ĵ and magnetic field = B0 . Its velocity at (x0, y0, 0 ) is (4î - 3ĵ). The value of x0 isOptions
A.
B.
C.
D.
Solution
From work energy theorem
W = ᐃKE ⇒ qE0x0 =
(42 + 32) ⇒ x0 = 
.
W = ᐃKE ⇒ qE0x0 =
(42 + 32) ⇒ x0 = .Create a free account to view solution
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