Magnetic field due to currentHard
Question
There exists a uniform magnetic and electric field of magnitude 1 T and 1 V/m respectively along positive y-axis. A charged particle of mass 1 kg and of charge 1 C is having velocity 1 m/s along x-axis and is at origin at t = 0. Then the co-ordinates of particle at time π seconds will be -
Options
A.(0, 1, 2)
B.(0, - π2/2, - 2)
C.(2, π2/2, 2)
D.(0, π2/2, 2)
Solution
T =
= 2π ⇒ R =
= 1m
At t = π; charge will complete half circle.
∴ x = 0 ; y =
z = 2R = 2m
At t = π; charge will complete half circle.
∴ x = 0 ; y =
z = 2R = 2m
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
Two infinitely long linear conductors are arranged perpendicular to each other and are in mutually perpendicular planes ...Consider the following statements regarding a charged particle in a magnetic field. Which of the statements are true ?...Due to the flow of current in a circular loop of radius R, the magnetic field produced at the centre of the loop is B. T...When direct current passed through a spring then it :-...′SI′ unit of magnetic flux is :-...