Momentum and CollisionHard
Question
A narrow tube completely filled with a liquid is lying on a series of cylinder as shown in figure. Assuming no sliding between any surface, the value of acceleration of the cylinders for which liquid will not come out of the tube from anywhere is given by


Options
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D.
Solution

In pure rolling acceleration of the tube = 2a
PA = Patm + ρ(2a)L (from horizontal)
PA = Patm + ρgH (from vertical)
⇒ a =
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